What is the specific heat capacity 82.4g of a metal that is absorbed 846 joules of heat as the temperature increases from 25c to 67c

Specific heat capacity = 0.24 j/g.°C

Explanation:

Given data:

Mass of metal = 82.4 g

Heat absorbed = 846 j

Change in temperature = 67°C - 25°C

Specific heat capacity = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 67°C - 25°C

ΔT = 42°C

Q = m.c. ΔT

846 j = 82.4 g . c. 42°C

c = 846 j / 3460.8 g.°C

c = 0.24 j/g.°C

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a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.