At 700 k, the rate constant for the following reaction is 6.2x 10-4 min-1. how many minutes are requiredfor 20 percent of a sample of cyclopropane to isomerize topropane?
c3h6(> c3h6(propane)
a. 1,120 min
b. 360 min
c. 3710 min
d. 1.4 x 10-4 min
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360 minutes are required for 20 percent of a sample of cyclopropane to isomerize topropane.

Explanation:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

As the units of rate constant is , the reaction follows first order kinetics.

Expression for rate law for first order kinetics is given by:

where,

k = rate constant  =

t = time for decomposition = ?

a = let initial amount of the reactant = 100

x = amount decayed =

a - x = amount left after decay process  = 100-20= 80

Thus 360 minutes are requiredfor 20 percent of a sample of cyclopropane to isomerize topropane.

if two electrons have the same n, the same ℓ, and the same ml, then they are in the same orbital. the pauli exclusion principle states that no two identical fermions (a fancy word for electrons and other subatomic particles like electrons) may occupy the same quantum state in an atom simultaneously.