What is the period of oscillation of an electron that is bouncing up and down in response to the passage of a packet of red lgiht?

2.33*10^-15 s

Explanation:

We need to estimate the period of oscillation of an electron that bounced up/down due to the effects of a passing packet of red light. The period of oscillation is the wavelength of the red light divided by the speed of the red light. We know that:

V = f*λ

where V = speed of the red light = 3*10^8 m/s

f = frequency = 1/T where T is the period of oscillation in seconds (s)

λ = the wavelength of the red light = 0.7*10^-6 m

Thus:

V = λ/T

T = λ/V = (0.7*10^-6)/(3*10^8) = 2.33*10^-15 s

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :