"a sample of air at 7.50 atm is cooled from 448k to 224k. if the volume remains constant, what is the final pressure?

P/T = constant (T = absolute temperature)

P1 = 7.5 atm

T1 = 224 K

P2 = ?

T2 = 448 K

P1/T1 = P2/T2

P2 = (T2/T1)*P1 = (448/224)*(7.5 atm) = 15.00 atm

Explanation:

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Explanation:

Applying gas law formulae:

P1/T1 = P2/T2

Where P1 = initial pressure (atm) = 7.5

T1 = initial temperature in Kelvin(K) = 448

P2 = final pressure (atm) = unknown

T2 = final temperature in Kelvin(K) = 224

From the above Formula make P2 the subject of formula

P2 = P1T2/T1

P2 = 7.50*224/448

P2 = 1680/448

P2 = 3.75ATM

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.