When heated up with propanoyl chloride, which of the following nitrogen-cont compounds would not result in an amide? a. triethylamine b. aniline c. dibutylamine d. methylamine e. ammonia

Option A is correct. A tertiary amine will not form an amide with acyl chlorides they can only transform acyl chlorides into ketenes.

Explanation:

(a). Reaction of acyl chloride with aniline: Aniline is the simplest primary amine. The -NH2 group is attached directly to the benzene ring. The equation of reaction is given below;

CH3COCl + 2C6H5NH2> CH3CONHC6H5 +C6H5NH3Cl.

The products of the reaction are The products are N-phenylethanamide,C6H5NH2 and phenylammonium chloride, C6H5NHCl.

(b). Reaction of acyl chloride with primary and secondary amine:

The -NH2 is attached to an alkyl group for the primary and secondary amine. Typical reaction equation for a primary amine with acyl chloride is given below;

CH3COCl + CH3NH2> CH3CONHCH3 + HCl.

The HCl will further react with NH3 to produce The salt is called methylammonium chloride.

(c). Reaction of acyl chloride with amine: the equation of reaction is given below;

CH3COCl + NH3 > CH3CONH2 + HCl.

The hydrogen chloride produced reacts with excess ammonia to form ammonium chloride;

NH3 + HCl > NH4Cl.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml