The molal freezing point constant of water is -1.86. at what temperature will a solution containing 8.27 g of cacl2?

Temperature of fussion, for the solution is -0.41°C

Explanation:

To solve this we need to apply the colligative property, freezing point  the pression.

ΔT = Kf . m . i

ΔT = T° f pure solvent - T° f solution

Kf= cryoscopic constant (1.86° C / m for water)

m = molality (mol of solute/ 1kg of solvent)

i = Van't Hoff factor (number of ions dissolved in solution)

CaCl₂ → Ca²⁺ + 2Cl⁻   (for this salt, i = 3)

Molar mass calcium chloride = 110.98 g/m

8.27 g/ 110.98 g/m = 0.0745 m

0°C - T°f solution = 0.0745 m . 1.86°C /m . 3

0°C - T°f solution = 0.41°C

T°f solution = - 0.41°C

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.