Calculate horxn for the following reaction: h3aso4(aq) + 4 h2(g) --> ash3(g) + 4 h2o(l)(hof [ash3(g)] = 66.4 kj/mol; hof [h3aso4(aq)] = -904.6 kj/mol; hof [h2o(l)] = -285.8 kj/mol)

The Standard enthalpy of reaction:

Explanation:

Given- Standard Heat of Formation:

= -904.6 kJ/mol

= 0 kJ/mol,

= +66.4 kJ/mol

= -285.8 kJ/mol

Given chemical reaction: H₃AsO₄(aq) + 4H₂(g) → AsH₃(g) + 4H₂O(l)

The standard enthalpy of reaction: = ?

To calculate the Standard enthalpy of reaction (), we use the equation:

Therefore, the Standard enthalpy of reaction:    

i think   the answer is c hope i'm right

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.