the ammonia/ammonium buffer system is used to optimize polymerase chain reactions (pcr) used in dna studies. the equilibrium for this buffer can be written as nh4+(+(aq)+nh3(aq) calculate the ph of a buffer that contains 0.045 m ammonium chloride and 0.095 m ammonia. the ka of ammonium is 5.6×10? 10. express your answer using two decimal places.

The pH of the buffer system is 9.57

Explanation:

Step 1: Data given

Molarity of NH4Cl = 0.045 M

Molarity of NH3 = 0.095 M

Ka of ammonium is 5.6*10^-10

 pKa = -log (5.6 * 10^-10) = 9.25

Step 2: The balanced equation

NH4+(aq) ⇆ H+(aq) + NH3(aq)

Step 3: Calculate the pH of the buffer

pH = pKa + log[NH3]/[NH4+]

pH = 9.25 + log(0.095/0.045)

pH = 9.57

The pH of the buffer system is 9.57

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )