What is the final concentration if a 50.0 ml sample of a 15% h2so4 solution is added to water to give a final volume of 250 ml?

1.5% h2so4 solution

25% h2so4 solution

10% h2so4 solution

3% h2so4 solution

The answer to your question is 3% H2SO4 solution

Explanation:

Data

Concentration 2 = C₂ = ?

Concentration 1 = C₁ = 15 %

Volume 1 = V₁ = 50 ml

Volume 2 = V₂ = 250 ml

Formula

             C₁V₁  = C₂V₂

Solve for C₂

             C₂ = C₁V₁ / V₂

Substitution

             C₂ = (15)(50) / 250

Simplification and result

             C₂  = 3 %

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.