Asample of a compound contains 30.0 g c and 5.05 g h. its molar mass is 78.12 g/mol. what is the compound’s molecular formula?
ch
c2h2
c6h6
c6h

The relative atomic mass of C is 12 g. So, to calculate how many atoms of C there are, we will divide 30 g by 12 g:
30 g ÷ 12 g = 2.5

The relative atomic mass of H is 1 g. So, to calculate how many atoms of C there are, we will divide 5.05 g by 1 g:
5.05 g ÷ 1 g = 5.05 ≈ 5

Now, let's calculate the ratio of C and H atoms:


This means there are 2 H atoms more than C atoms and therefore, the compound’s molecular formula is CH₂.

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