According to the equation above, how many moles of potassium chlorate, kclo3, must be decomposed to generate 1.0 l of o2 gas at standard temperature and pressure?

Moles of potassium chlorate = 0.02976 moles

Explanation:

At standard pressure and temperature,

22.4 L of a gas consists of 1 mole

Thus, given, volume of = 1.0 L

So,

1 L of a gas consists of mole

Moles of oxygen gas = 0.04464 moles

The reaction is shown below as:-

3 moles of oxygen gas are produced when 2 moles of potassium chlorate undergoes reaction.

So,

1 mole of oxygen gas are produced when moles of potassium chlorate undergoes reaction.

Thus,

0.04464 mole of oxygen gas are produced when moles of potassium chlorate undergoes reaction.

Moles of potassium chlorate = 0.02976 moles

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explanation:

1. a)c-14 has two more protons

2. d)they have different numbers of protons, neutrons, and valence electrons; they are all gases at room temperature.

3. c) iron and nickel.