"professor offenrokker has a solution that is 6.0 x 10-3 m of hcl of a solution. however, he needs 450 ml of a 6.0 x 10-4 m hcl solution. how much of the stock solution will he need to make the dilute solution? "

Answer : The volume of the stock solution he need to make the dilute solution will be, 45 mL

Explanation :

According to dilution dilution law:

where,

= molarity of concentrated solution

= molarity of dilute solution

= volume of concentrated solution

= volume of dilute solution

Given:

=

=

= ?

= 450 mL

Now put all the given values in the above formula, we get:

Therefore, the volume of the stock solution he need to make the dilute solution will be, 45 mL

the mass of the cathode increases because ions from the solution get reduced to atoms and become part of the cathode.

explanation:

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