Which one of the following sets of quantum numbers can correctly represent a 3p orbital? a) (n = 3 l = 1, ml = 2)b) (n = 1, l = 3, ml = 3)c) (n = 3, l = 2, ml = 1)d) (n = 3, l = 1, ml = -1)e) (n = 3, l = 0, ml = 1)

d) (n = 3, l = 1, mₗ = -1)  

Explanation:

A 3p orbital must have n = 3.

That eliminates Option (a), because it has n = 1.

A p orbital must have l = 1.

That eliminates Options (b), (c), and (e), because they have l = 3, 2, and 0.

The only correct option is

n = 3, l = 1, mₗ = -1

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.