Astudent preparing for the experiments inadvertently adds an additional 400 ml of the same acid solution to the dissolution vessel. what will be the new poh of this solution?

POH= 13

Explanation:

A student preparing for the experiments inadvertently adds an additional 400 mL of the same acid solution to the dissolution vessel. What will be the new pOH of this solution?

PH is the measure of the degree of acidity of a solution.

POH is the measure of the degree of alkalinity of a solution

Note that  pH + pOH = 14

if concentration remains the same, then volume changes will not affect pH.

The pH of the solution is given as

PH= -log[H+].

For this experiment, the dissolution vessel contains 0.1 M HCl, no matter the initial volume of the acid solution

For the molar concentration of the cation, we can propose that  a strong acid will  dissociate completely,

[H+] = 0.1 = 1 x 10-1 M

. substituting the concentration of the cation

PH=-log[1 x 10-1] = 1.

Note that  pH + pOH = 14 for any aqueous solution.

we say that

the pOH = 14 - pH.

pOH = 14-1 = 13.

im not exactly sure but i think its b!