If 5.0 grams of sucrose, c12h22o11, are dissolved in 10.0 grams of water, what will be the boiling point of the resulting solution?

Answer : The boiling point of the resulting solution is,

Explanation :

Formula used for Elevation in boiling point :

or,

where,

= boiling point of solution = ?

= boiling point of water =

= boiling point constant  =

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

= mass of solute (sucrose) = 5.0 g

= mass of solvent (water) = 10.0 g

= molar mass of solute (sucrose) = 342.3 g/mol

Now put all the given values in the above formula, we get:

Therefore, the boiling point of the resulting solution is,

answer: enthalpy

explanation:

for a exothermic reaction, the energy is released i.e. the energy of the products is lower than the energy of the reactants.

= enthaply

= energy of products

= energy of reactants

as , thus comes out to be negative. negative value of enthalpy shows that the reaction is exothermic.

i think its 100.

hope this !