The equilibrium constant for the reaction h2 (g) + i2 (g) < ==> 2 hi (g)

kp is 54.4. what percent of i2 (g) will be converted to hi (g) is 0.200 moled each of h2 (g) and i2 (g) are mixed and allowed to come to equlibrium in a 1.00 liter container?

The percentage of I2 converted = 78.6 %

Explanation:

Write down the given values

Kp= 54.4

The percentage of I2 will be converted to HI is 0.200 moled each of H2 and I2.

It should come to an equilibrium in 1.00 lit container .

Change in I2 (iodine) and H2 (hydrogen)  = x in each

Change in HI = 2x

total ni (nickel)

number of moles = 0.2 -x + 0.2 -x + 2x

=0.4 moles

Mole fractions :

I2 = 0.2-x / 0.4 H2

=0.2-x  / 0.4 HI

= 2x /0.4

Kp = HI ^2 / H2* I2

= (2x) ^2 / (0.2-x) ^2 = 54.4

by  taking square root:

2x / 0.2-x = 7.375

= x=0.157

percentage of I2 converted = 78.6 %

chemical changes occur when a substance combines with another to form a new substance, called chemical synthesis or, alternatively, chemical decomposition into two or more different substances. these processes are called chemical reactions and, in general, are not reversible except by further chemical reactions. some reactions produce heat and are called exothermic reactions and others may require heat to enable the reaction to occur, which are called endothermic reactions. understanding chemical changes is a major part of the science of chemistry.