1. how many carbon atoms are in .76 mol of carbon atoms

2. 5.6 x 1022 particles, how many moles is that?

3. the mass in grams of 0.25 mol of water?

4.how many moles are in 48.2 g of calcium chloride (cacl2)?

5. 11.2 l container of chlorine gas at standard temperature and pressure. how many moles of chlorine gas are in the container? 1 mol of gas in 22.4 l at standard temperature/ pressure.

6. the empirical formula of a compound that is 25.9% n and 74.1% o by mass.

answer any of each also show how that would

1. 4.57x10²³ atoms ; 2. 0.093 moles; 3. 4.5 grams ; 4. 0.434 moles , 5. 0.5 mol of Cl₂ ; 6. N₂O

Explanation:

1. 1 mol has NA atoms

0.76 mol will have (0.76 . 6.02x10²³) = 4.57x10²³ atoms

2. 6.02x10²³ particles are contained in 1 mol

5.6x10²² particles are contained in (5.6x10²²  . 1) / 6.02x10²³ = 0.093 moles

3. 1 mol of water weighs 18 g

0.25 mol . 18g/m = 4.5 grams

4. Molar mass of CaCl₂ = 110.98 g/m

Mol = Mass / molar mass → 48.2 g / 110.98 g/m = 0.434 moles

5. If the volume of Cl₂ at STP (as 1 mol of any gas) is 22.4L, and now we have the half of volume, we will have the half of moles, though. So, we have in the container 0.5 mol of Cl₂

6. 25.9% N and 74.1% O means that in 100 g of compound, we have 25.9 g of N and 74.1 g of O.

25.9 g of N / 14 g/m = 1.85 mol

74.1 g of O / 16 g/m = 4.63 mol

We divide the mol with the lowest value

4.63 mol / 1.85 mol = 2.5

1.85 mol / 1.85 mol = 1

N₂O

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )