3) how much energy does it take to condense 26.5 g of h0 at 100°c?
equation:

59.89 KJ

Explanation:

Data Given:

mass of H₂O (m) = 26.5 g

heat released (Q) = ?

Solution:

This question is related to the latent heat of condensation.

Latent heat of condensation is the amount of heat released when water vapors condenses to liquid.

Formula used

Q = m x Lc . . . . . (1)

where

Lc = specific latent heat of condensation

Latent heat of vaporization of water is exactly equal to heat of condensation with -ve charge

So, Latent heat of vaporization of water has a constant value

Latent heat of vaporization of water = 2260 J/g

So

Latent heat of condensation of water will be = - 2260 J/g

Put values in eq. 1

            Q = (26.5 g) x (- 2260 J/g)

            Q = - 59890 J

convert J to kJ

1000 J = 1 KJ

59890 J = 59890 / 1000 = 59.89 KJ

So, 59.89 K of heat will be released. negative sign indicate release of energy for condensation

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer