Answer !
refer to the attached table for information about gold and mercury. then choose which statements are true about equal sample sizes of
the metals. select all that apply.
1) the mercury will change temperature at a much faster rate under the same heating conditions.
2) the two metal samples will change temperature at about the same rate.
3) the gold would float if placed in the mercury.
4) the gold would sink to the bottom if placed in the mercury.

Explanation:

To solve this problem first of all we will understand the specific heat capacity.

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

The substances with higher value of specific heat capacity require more heat to raise the temperature by one degree as compared the substances having low value of specific heat capacity.For example,

The specific heat capacity of gold is 0.031 cal/g.°C and for mercury is 0.033 cal/g.°C. So, mercury take a time to increase its temperature by one degree by absorbing more heat while gold will heat up faster by absorbing less amount of heat.

1)  The mercury will change temperature at a much faster rate under the same heating conditions.

This statement is false because specific heat capacity of gold is less than mercury so gold will change the temperature faster.

2) The two metal samples will change temperature at about the same rate.

There is small difference in specific heat of both metals so gold will change the temperature little faster than mercury.

3)  The gold would float if placed in the mercury.

The density of gold is greater than mercury so it will sink into mercury.

4) The gold would sink to the bottom if placed in the mercury.

Yes thus statement is true.

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.

c. orbital shape i hope this is correct