An atom emits a photon of wavelength 1.08 meters. what is the energy change occurring in the atom due to this emission? (planck's constant is 6.626 × 10-34 joule seconds, the speed of light is 2.998 × 108 m/s)

To proceed with the problem we need the formula: 
E = hc/λ where E is the energy emitted by the photon (required), h is the Planck's constant (6.626 × 10-34 joule seconds), c is speed of light (2.998 × 108 m/s), and λ is the wave length (1.08 m). Plugging in the given to the equation and solve for energy, you would get 1.83*10^-25 J