The distribution constant for a molecule x between n-hexane and water
is 13.5. calculate the percent of x remaining in the water phase that
was originally 0.0100 m in z after extraction of 50.0 ml of water with
4 extractions of 10.0 ml portions of n-hexane.

X = 0.005%

Explanation:

The concentration of X remaining in the water phase can be calculated using the next equation:

Where:

: is the concentration of A remaining in aqueous solution

: is the volume of water

: is the volume of the organic solvent

KD: is the distribution constant of X between water and the organic solvent

: is the original concentration of X

i: is the number of extractions with the organic solvent

The percent of X remaining in the water phase is:

I hope it helps you!    

can you list the answers so i can answer

answer: i have one answer

acids are substances that ionize (break off) in an aqueous solution to produce hydrogen (h+) ions

explanation:

hope this and sorry i could only come up with one answer!