Find the ph of a 0.00580 m solution of the strong
basekoh.

11.76

Explanation:

Potassium hydroxide is a strong base that dissociates completely according to the following reaction.

KOH(aq) → K⁺ + OH⁻

Then, the concentration of OH⁻ will be 0.00580 M.

The pOH of the solution is:

pOH = -log [OH⁻]

pOH = -log 0.00580 = 2.24

We can calculate the pH using the following expression.

pH + pOH = 14

pH = 14 - pOH = 14 - 2.24 = 11.76

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :