If you had 10.00 ml of acetic acid that you titrated with .100 m naoh, and you used 45.15 ml of that base to get a light pink color, what is the concentration of your acetic acid?

a) .904m
b) .452m

0.4515 M

Explanation:

In case of titration , the following formula can be used -

M₁V₁ = M₂V₂

where ,

M₁ = concentration of acid ,

V₁ = volume of acid ,

M₂ = concentration of base,

V₂ = volume of base .

from , the question ,

M₁ = ? M

V₁ = 10.0 mL

M₂ = 0.100 M

V₂ = 45.15 mL

Using the above formula , the molarity of acid , can be calculated as ,

M₁V₁ = M₂V₂

M₁ * 10.0mL = 0.100 M  * 45.15 mL  

M₁ = 0.4515 M

Hence, the concentration of the acetic acid = 0.4515 M

hi,

the answer is d, it has indefinite shape but definite volume.

hope this !

where is the following

explanation: