How many grams of sulfur are present in 83.2 grams of
sulfurdioxide?

41.6 g

Explanation:

Calculation of the moles of as:-

Mass = 83.2  g

Molar mass of = 64.066 g/mol

The formula for the calculation of moles is shown below:

Thus,

From seen from the formula,

1 mole of sulfur is present in 1 mole of

So,

1.2987 mole of sulfur is present in 1.2987 mole of

Moles of sulfur = 1.2987 mol

Molar mass of sulfur = 32.065 g/mol

Mass = Moles*Molar mass = = 41.6 g