The gas in an engine cylinder is compressed until it has a volume of 0.045 liter and an absolute pressure of 28 atmospheres. if the engine cylinder contains 0.020 mole of gas, what is its temperature

the temperature of the gas is k.

pv=nrt

The temperature of the gas is 767.7 Kelvin

Explanation:

Step 1: Data given

The volume of the gas = 0.045 L

Pressure = 28 atm

Number of moles = 0.020 moles of gas

Step 2: Calculate the temperature of the gas

p*V = n*R*T

T = (p*V)/(n*R)

⇒ with p = the pressure = 28 atm

⇒ with V = the volume of the gas = 0.045 L

⇒ with n = the number of moles of gas = 0.020 moles

⇒ with R = the gas constant = 0.08206 L*atm/ K*mol

T = (28*0.045)/(0.020*0.08206)

T = 767.7 K

The temperature of the gas is 767.7 Kelvin

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