Use the data table to answer the questions below mass of
evaporating .07g mass of
evaporating dish plus .12 g mass of
evaporating dish and anhydrous crystals .58g
if the hydrate used in the lab for the above data table is
mgso4.7h20, then calculate the theoretical % water in the hydrate
15%
51%
73%
95%
100%

Option B is correct : 51%

Explanation:

Data Given:

Hydrates used in lab = MgSO₄ .7H₂O

% water in hydrate = ?

Solution:

As we look for the the theoretical % water in hydrates

So

For H₂O atomic masses are given below

H = 1 g/mol

O = 16 g/mol

Then find the total mass of H₂O in hydrated salt

           7H₂O = 7 (2x1 +1x16) g/mol

           7H₂O = 7 (2+16) g/mol

           7H₂O = 7 (18) g/mol

Now,

> find total Molar Mass of Molecule:

       Molar Mass of MgSO₄ • 7H₂O = [24 + 32 + 16x4] + 7(2+16)

       Molar Mass of MgSO₄ • 7H₂O = [24+ 32 + 64] + 126

       Molar Mass of MgSO₄ • 7H₂O = [120] + 126

Now to find the mass by percent of (water) H₂O

Formula used to find the mass by percent of a component

Percent composition of H₂O = mass of H₂O in Molecule / molar mass of MgSO₄•7H₂O x 100%

Put the values in above formula

        Percent by mass of H₂O = 126 (g/mol) / 246 (g/mol) x 100%

        Percent by mass of H₂O = 0.51 x 100%

        Percent by mass of H₂O = 51%

So,

Option B is correct : 51%

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