Mgcl2 has a concentration of 0.054 m in the ocean. how many grams are present in 25ml of sea water

0.129g MgCl2

Explanation:

For this we need to understand the concept of molarity.

Molarity is number of moles of solute/litres of solution

M=n/L

Here we are given molarity of 0.054M and volume of 25ml. we just plug this in formula to find moles of MgCl2

0.054=x/(25/1000) (we divided 25 by 1000 to convert it to litres of solution)

x=0.00135 moles of MgCl2 (we are not done yet the question asks for grams so to convert to grams we multiply by molar mass of MgCl2.)

0.00135molesMgCl2 x 95.211g MgCl2/1molMgCl2

= 0.129g MgCl2

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