Chemistry, 13.01.2020 01:31 rodfam13716

7. copper + sulfuric acid yield copper (ii) sulfate + water + sulfur dioxide

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Answer from: neptunesx

The chemical equation for the given reaction has been:

$\rm 7\;Cu\;+\;H_2SO_4\;\rightarrow\;CuSO_4\;+\;H_2O\;+\;SO_2$

The chemical equation has been the representation of the equation with the chemical symbols for the reactants and products involved in the reaction.

The word equation has been the representation of the reaction in the word form of reactants and products.

Chemical equation

The word equation has been given as:

7 copper + sulfuric acid yields copper (II) sulfate + water + sulfur dioxide

The reaction has been a redox reaction for the reduction of sulfuric acid and oxidation of copper.

The chemical equation for the given reaction has been:

$\rm 7\;Cu\;+\;H_2SO_4\;\rightarrow\;CuSO_4\;+\;H_2O\;+\;SO_2$

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Answer from: treaustin656

Full Question:

Write the word equations below as chemical equations and balance:

copper + sulfuric acid yield copper (II) sulfate + water + sulfur dioxide

Cu +2 H₂SO₄ = CuSO₄ +2H₂O +SO₂.

Explanation:

Copper is a metal which is sitting just below the hydrogen in the reactivity series.

When metallic copper is put in dilute sulphuric acid and the solution is heated, the solution forms a bluish gdiscoloration with evolution of a gas with smell of brunt sulphur.

Its a redox reaction as the metallic copper gets oxidized to cupric ions and the sulphuric acid gets reduced to Sulphur dioxide gas.

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the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. $hbr$ completely dissociates to $h^+$ and $br-$ ions. a is incorrect because $h_2s$ does not fully ionize to $h^+$ and $hs^-$ ions and some remain as the compound $h_2s$ . c and d are incorrect because, $li_2o$ and $libr$ do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise, if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both $li_2o$ and $libr$ have a complete octet so can not accept any electrons which disqualifies them as acids.

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