The starting pressure of a 15°c system was 1.50 atm. if the pressure rose to 1216 torr, what is the new temperature in celsius?

The new temperature is 34.21 °C

Explanation:

Step 1: Data given

Temperature of the system = 15°C

Pressure at 15°C is 1.50 atm

The pressure rose to 1216 torr (=1216/760 = 1.6 atm)

Step 2: Calculate the new temperature

P1/T1 = P2/T2

⇒ with P1 = the initial pressure = 1.50 atm

⇒ with T1 = the initial temperature = 15°C = 288.15 K

⇒ with P2 = the initial pressure = 1.60 atm

⇒ with T2 = the initial temperature = TO BE DETERMINED

T2 = T1 * (P2 / P1)

T2 = 288.15 * (1.60/1.50)

T2 = 307.36 K = 34.21 °C

The new temperature is 34.21 °C

the electronic configuration of an atom with eight electrons is 1s²2s²2p⁴. the orbital diagrams are shown in the figure.

as per the hunds rule:

1. electrons tend to avoid being in the same orbital as per as practicable.

2. electrons in different orbitals of the same energy will have their spin parallel.

this can be illustrated from the multiplicity of the orbitals of the atom. as there are four electrons in the p orbital and p orbital has 3 sub-shells. the electrons can be fed in different ways as shown in the figure but the correct orbital diagram will be as per the hunds rule.