Acompression at a constant pressure of 200 kpa is performed on 8.00 moles of an ideal monatomic gas. the compression reduces the volume of the gas from 0.200 m3 to 0.120 m3. how much work was done by the gas during this process?

workdone = 16kJ

Explanation:

Workdone  for an Isobaric process = PΔV (1)

                                  = P (V₁-V₂)(2)

P = 200kPa ; 200,000 N/m²

V₁ = 0.200 m³

V₂ =  0.120 m³

Substituting into (2) we have:

Workdone =  200,000 (0.200-0.120)

                  =   200,000 (0.080)

                  =16,000Nm

                  = 16,000Joules

                  = 16kJ

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.