Elvin is asked to analyze a 0.353 gram sample of metal. he measures the amount of heat
released by cooling it from 50.0 °c to 22.0 °c as 2.28 j. what is the specific heat of this metal?
what metal could this be?

c = 0.23 j/g.°C

The metal could be silver

Explanation:

Given data:

Mass of metal = 0.353 g

Initial temperature = 50°C

Final temperature = 22.0°C

Heat release = -2.28 j

Specific heat of metal = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 -T1

ΔT =  22.0°C - 50°C

ΔT = -28°C

Q = m.c. ΔT

- 2.28 j = 0.353 g × c × -28°C

c = - 2.28 j  / 0.353 g × -28°C

c = - 2.28 j  / 9.884g.°C

c = 0.23 j/g.°C

The metal could be silver.

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