Enter the coefficients that balance the tarnishing
reaction equation. (type 1 for no coefficient.)
i ag(s) + h2s(g) – ag, s(s) + h2(g)

2Ag(s) + 1H2S(g) → 1Ag2S(s) + 1H2(g)

Explanation:

Step 1: Data given

Ag(s) + H2S(g) → Ag,S(s) + H2(g)

Ag has and oxidation number of +1

S has an oxidation number of -2

H has an oxidation number of +1

Step 2: The balanced equation

Ag+ + 2H+ + S^2- →

The silver ion and the sulfur ion will bind, but we need 2 silver atoms to bind with 1 sulfur atom.

2 H- atoms will appear as H2.

The balanced equation is:

2Ag+ + 2H+ +S^2- → Ag2S + H2

2Ag(s) + 1H2S(g) → 1Ag2S(s) + 1H2(g)

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.