N2(g) + 3h2(g) → 2nh3(g)
how many moles of ammonia are produced when 0.60 mol of nitrogen reacts with hydrogen?

The number of moles of ammonia that are produced is 1.20 moles

From the question,

We are to determine the number of moles of ammonia that are produced

From the given balanced chemical equation

N₂(g) + 3H₂(g) → 2NH₃(g)

This means

1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia.

Now, to determine the number of moles of ammonia that would be produced from the 0.60 mole of nitrogen

Since

1 mole of nitrogen reacts to produce 2 moles of ammonia

Then,

0.60 mole of nitrogen will react to produce 2 × 0.60 moles of ammonia

2 × 0.60 = 1.20 moles

Hence, the number of moles of ammonia that are produced is 1.20 moles

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The answer to your question is 1.2 moles

Explanation:

Reaction

                            N₂(g) +  3H₂ (g)    ⇒  2NH₃

Check if the reaction is balanced

                     Reactants            Elements       Products

                            2                          N                    2

                            6                          H                    6

As the number of reactants is equal to the number of products, this reaction is balanced.

Now, calculate the moles of ammonia produced using proportions

                      1 mol of nitrogen     2 moles of ammonia

                     0.6 mol of nitrogen      x

                     x = (0.6 x 2) / 1

                     x = 1.2 / 1

                     x = 1.2 moles of ammonia are formed