Iron(iii) oxide reacts with carbon monoxide to produce iron and carbon; fe2o3(s)+3co(> 2fe(s)+3co2(g). a) what is the percent yield for the reaction if 65.0 g of iron(iii) oxide produced 15.0 g of iron? b) what is the percent yield for the reaction if 75.0 g of carbon monoxide produces 85.0 g of carbon dioxide?

a) %yield= 33.00 %

b) %yield= 72.1 %

Explanation:

Step 1: Data given

Mass of iron(III) oxide = 65.0 grams

mass of iron produced = 15.0 grams

Molar mass of Fe2O3 = 159.69 g/mol

Molar mass of CO = 44.01 g/mol

Step 2: The balanced equation:

Fe2O3(s)+3CO(g) →2Fe(s)+3CO2(g)

Step 3: Calculate moles of Fe2O3

Moles Fe2O3 = 65.0 grams / 159.69 g/mol

Moles Fe2O3 = 0.407 moles

Step 4: Calculate moles Fe

For 1 mole Fe2O3 we'll have 2 moles Fe

For 0.407 moles Fe2O3 we'll have 2*0.407 = 0.814 molesFe

Step 5: Calculate mass Fe

Mass fe = 0.814*55.845 g/mol

Mass Fe = 45.46 grams = theoretical yield

Step 6: Calculate % yield

%yield = (actual yield/theoretical yield)*100%

%yield = (15.0/45.46)*100%

%yield= 33.00 %

b) What is the percent yield for the reaction if 75.0 g of carbon monoxide produces 85.0 g of carbon dioxide?

Step 1: Data given

Mass of CO = 75.0 grams

mass of CO2 produced = 85.0 grams

Molar mass of CO = 28.01  g/mol

Molar mass of CO2 = 44.01 g/mol

Step 2: The balanced equation:

Fe2O3(s)+3CO(g) →2Fe(s)+3CO2(g)

Step 3: Calculate moles of CO

Moles CO = 75.0 grams / 28.01 g/mol

Moles CO = 2.68 moles

Step 4: Calculate moles CO2

For 1 mole Fe2O3 we need 3 moles CO to produce 2 moles Fe and 3 moles CO2

For 2.68 moles CO we'll have 2.68 moles CO2

Step 5: Calculate mass CO2

Mass CO2= 2.68 * 44.01 g/mol

Mass CO2 = 117.95 grams = theoretical yield

Step 6: Calculate % yield

%yield = (actual yield/theoretical yield)*100%

%yield = (85.0/117.95)*100%

%yield= 72.1 %

in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

explanation: