22.5 ml of an hno3 solution were titrated with 31.27 ml of a .167 m naoh solution to reach the equivalence point. what is the molarity of the hno3 solution

M₂ = 0.23 M

Explanation:

Given data:

Volume of HNO₃ = 22.5 mL

Volume of NaOH = 31.27 mL

Molarity of NaOH = 0.167 M

Molarity of HNO₃ = ?

Solution:

M₁ = Molarity of NaOH

V₁ = Volume of NaOH

M₂ = Molarity of HNO₃

V₂ = Volume of HNO₃

M₁V₁ = M₂V₂

0.167 M × 31.27 mL = M₂ × 22.5 mL

5.2 M. mL = M₂ × 22.5 mL

M₂ =  5.2 M. mL /22.5 mL

M₂ = 0.23 M

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