Asolution of methanol, ch3oh, in water is prepared by mixing together 128 g of methanol and 108 g of water. the mole fraction of methanol in the solution is closest to

Mole fraction of methanol = 0.4

Explanation:

Molar mass methanol: 32 g/mol

Molar mass water: 18 g/m

Mol = Mass / Molar mass

128 g / 32 g/m = 4 moles of CH₃OH

108 g / 18 g/m = 6 moles of H₂O

Mole fraction of methanol = Moles of methanol / Moles of methanol + Moles of H₂O

4 / 10 = 0.4

The mole fraction of methanol is  0.4

The molar mass of methanol is = 32 g/mol

The number of moles of methanol is = 128 g/32 g/mol = 4 moles

The molar mass of water is 18 g/mol

The number of moles of water = 108 g/18 g/mol = 6 moles

Total number of moles = 6 moles + 4 moles = 10 moles

Mole fraction of methanol = 4 moles/ 10 moles = 0.4

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16

explanation:

the marks go by 4s