Study this chemical reaction: pb + 2cl2 = pbcl4then, write balanced half-reactions describing the oxidation and reduction that happen in this reaction. oxidation: :

Oxidation: Pb → Pb⁴⁺ + 4 e⁻

Reduction: 2 Cl₂ + 4 e⁻ → 4 Cl⁻

Explanation:

Let's consider the following redox reaction.

Pb + 2 Cl₂ ⇄ PbCl₄

We can identify both half-reactions.

Oxidation: Pb → Pb⁴⁺ + 4 e⁻

Reduction: 2 Cl₂ + 4 e⁻ → 4 Cl⁻

Pb is oxidized and its oxidation number increases from 0 to 4+ while Cl₂ is reduced and its oxidation number decreases from 0 to 1-.

d. temperate deciduous forest

on passing the small ampere of electric current through the tube made of ar and hg of cfl generates uv rays which excites the fluorescent and thus emits the high radiation by consumption of just 5- 12 w in comparison to incandescent light which requires more power such as around 40 - 55 w to lighten.

moreover the life span of fluorescent or cfl is around 8000 h whereas the life span of incandescent is around 1200 h

hence, the building installed with incandescent lights bears more electricity bill.