An aerosol can filled with propane gas occupies a volume of 250 ml at 23 c and 1.54 atm. if the conditions are changed to stp, what is the new volume in the can?

The new volume is 388 mL

Explanation:

Step 1: Data given

Volume = 250 mL = 0.250 L

Temperature = 23 °C = 296 Kelvin

Pressure = 1.54 atm

Step 2: Calculate number of moles

p*V =n*R*T

n = (p*V)/(R*T)

⇒ n = the number of moles = ?

⇒ V = the volume: the gas occupies = 0.250 L

⇒ The pressure of propane gas = 1.54 atm

⇒ Temperature = 23.0 °C = 296 Kelvin

 ⇒ R = The gas constant = 0.08206 L*atm/K*mol

n = (1.54 * 0.205 ) / ( 0.08206 * 296 )

n = 0.013 moles

Step 3: Calculate new volume

(P1*V1)/T1 = (P2*V2)/T2

⇒ with P1 = the initial pressure =  1.54 atm

⇒ with V1 = the initial volume = 0.250 L

⇒ with T1 = the initial temperature = 296 K

⇒ with P2 = 1.00 atm

⇒ with V2 = The new volume at STP

⇒ with T2 = 298 Kelvin

(1.54*0.250)/296 = (1.00 * V2)/298

V = 0.388 L = 388 mL

The new volume is 388 mL

it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.