How many milliliters of a 0.212 m hi solution are needed to reduce 20.5 ml of a 0.358 m kmno4 solution according to the following equation: 10hi + 2kmno4 + 3h2so4 → 5i2 + 2mnso4 + k2so4 + 8h2o

Volume = 0.17 L

Explanation:

For :

Molarity = 0.358 M

Volume = 20.5 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 20.5×10⁻³ L

Moles of :

According to the reaction shown below:-

2 moles of reacts with 10 moles of HI

Also,

1 mole of reacts with 5 moles of HI

So,

0.007339 mole of reacts with 5*0.007339 moles of HI

Moles of HI = 0.036695 moles

Volume = ?

Molarity = 0.212 M

So,

Volume = 0.17 L

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