What is the formula for copper(ii) phosphate? capitalization and punctuation count. how many atoms of phosphorus are in 7.10 mol of copper(ii) phosphate?

There are 8.55ₓ10²⁵ atoms of P, in 7.1 moles of Cu₃(PO₄)₂

Explanation:

Copper (II) ⇒ Cu²⁺

PO₄⁻³ → phosphate

3Cu²⁺  +  2PO₄⁻³  → Cu₃(PO₄)₂

1 mol of copper (II) phosphate has 2 mol of P, 8 moles of O and 3 moles of Cu.

Then, 7.10 moles of salt has (7.1  .2) = 14.2 moles of P

In 1 mol we find, NA atoms (6.02ₓ10²³)

In 14.2 moles we would find (14.2  .NA) = 8.55ₓ10²⁵ atoms