In an experiment 38.65 ml of 0.265 m kmno4 solution reacted with 18.78 ml of fe +2 solution. what was the molarity of the iron (ii) ion in solution?

2.73 M

Explanation:

The balanced reaction that takes place is:

MnO₄⁻ + 8H⁺ + 5Fe²⁺ → Mn²⁺ + 5Fe⁺³ + 4H₂O

Moles of MnO₄⁻ that reacted = 0.265 M * 38.65 mL = 10.24 mmol MnO₄⁻

Moles of Fe²⁺ that reacted = 10.24 mmol MnO₄⁻ * = 51.21 mmol Fe²⁺

Molarity of Iron (II) = 51.21 mmol Fe²⁺ / 18.78 mL =2.73 M