What is the ph of a solution made by diluting 1.00 ml of 0.10 m hcl with enough distilled water to make 1.00 l of solution?

The answer to your question is  pH = 4

Explanation:

Data

Volume 1 = V1 = 1 ml = 0.001 l

Concentration 1 = C1 = 0.1 M

Volume 2 = V2 = 1 l

Concentration 2 = C2 = ?

Process

1.- Find the new concentration of the solution

                    C₁V₂  = C₂V₂

Solve for C₂

                     C₂ = C₁V₁ / V₂

Substitution

                     C₂ = (0.1 x 0.001) / 1

Result

                     C₂ = 0.0001 M

2.- Find the pH of the solution

Formula

                pH = -log[H⁺]

Substitution

                pH = - log[0.0001]

Simplification

                pH = 4                  

i do not get it   at all