31.65 ml volume of 1.07 m fe(no3)3 is mixed with 44.96 ml of 0.79m fe(no3)3 solution. calculate the molar concentration of the final solution. save rounding until the end.

[Fe(NO₃)₃] = 0.90 M

Explanation:

Molarity = Mol/L

Total volume of solution: 31.65 mL + 44.96 mL = 76.61 mL

Let's determine the moles of salt ([M] . volume)

0.03165 L  . 1.07M = 0.0338 moles

0.04496L .  0.79M = 0.0355 moles

Total moles Fe(NO₃)₃ = 0.0338 + 0.0355 = 0.0693 moles

Volume of solution = 76.61 mL = 0.07661 L

0.0693 mol / 0.07661 L = 0.90 mol/L

The molar concentration of the final solution is 0.9057 M

Explanation:

Step 1: Data given

Volume of a 1.07 M Fe(NO3)3 solution = 31.65 mL = 0.03165 L

Volume of a 0.79 M Fe(NO3)3 solution = 44.96 mL = 0.04496 L

Step 2: Calculate moles of 1.07 M Fe(NO3)3 solution

Moles = molarity * volume

Moles = 1.07 M * 0.03165 L

Moles = 0.0338655 moles

Step 3: Calculate moles of 0.79 M Fe(NO3)3 solution

Moles = 0.79 M * 0.04496 L

Moles = 0.0355184 moles

Step 4: Calculate total moles

Total moles = 0.0339 + 0.0355

Total moles = 0.0693839 moles

Step 5: Calculate total volume

Total volume = 31.65 mL + 44.96 mL

Total volume = 76.61 mL = 0.07661 L

Step 6: Calculate molar concentration of the final solution

Concentration = moles / volume

Concentration = 0.0693839 moles / 0.07661 L

Concentration = 0.9057 M

The molar concentration of the final solution is 0.9057 M

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."

answer: a tank of height h is filled with water and sits on the ground. water squirts from a hole at a height y above the ground and has a range r. for two y values, 0 and h, r is zero. determine the value of y for which the range will be a maximum.

explanation: