I’m trying to do a graph on the combustion of ethanol, labelling the activation change and overall energy change, the picture is attached

Here's what I get  

Explanation:

Your graph should resemble the one below.

The ethanol and oxygen molecules must receive enough energy (perhaps from a match flame) to get over an activation energy barrier (Eₐ).

The products are lower in energy than the reactants, so the difference in energy is given off as heat (ΔH).

The overall energy change is

ΔH = Energy of products - energy of reactants

The products are lower in energy than the reactants, so the combustion of ethanol is exothermic.

answer; i believe that the correct answer is (a) potassium(k)