Amixture of nitrogen gas and oxygen gas has a total pressure of l.13 atm. if the partial pressure of oxygen is 0.43 atm, what is the partial pressure of nitrogen?

a) 1.56 atm
b) 1.13 atm
c) 0.70 atm
d) 0.38 atm

0.70 atm - Option C

Explanation:

Let's apply the mole fraction concept to solve this:

Partial pressure of a gas / Total pressure = Mole fraction of a gas.

In a mixture, sum of mole fraction from each gas = 1

Partial pressure of O₂ / Total pressure = Mole fraction of O₂

0.43 atm / 1.13 atm = 0.380

1 - 0.380 = 0.62 → Mole fraction N₂

Mole fraction N₂ = Partial pressure N₂ / Total pressure

0.62 = Partial Pressure N₂ / 1.13 atm

0.62 . 1.13 = 0.70 atm → Partial Pressure N₂