Aballoon has a volume of 1.2 l at a pressure of 1.1 atm and a temperature of 25°c. if the temperature changes to 75ºc and the volume changes to 6.7 l, what is the new pressure?

P₂ = 0.23 atm

Explanation:

Given data:

Initial volume = 1.2 L

Initial pressure = 1.1 atm

Initial temperature = 25 °C (25 +273 = 298 K)

Final temperature = 75°C(75+273 = 348 K)

Final volume = 6.7 L

Final pressure = ?

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₂ = P₁V₁ T₂/ T₁ V₂  

P₂ = 1.1 atm × 1.2 L × 348 K / 298 K × 6.7 L  

P₂ = 459.36 atm .L. K / 1996.6 k.L

P₂ = 0.23 atm