Adiprotic acid is composed of carbon, hydrogen and oxygen. it is 60.6% c, and 3.58% h by mass. a titration requires 25 ml of 0.850mnaoh to neutralize 5.692g of the acid. what is the molecular formula for diprotic acid?

a- c27h19012

b- c54h38024

c- c22h20o13

d- c12h15o4

e- c15h12o4

The molecular formula for diprotic acid is :

a)- C27H19012

Explanation:

It is given in the question that :

The titration requires 25 mL of 0.850M NaOH to neutralize 5.692g of the acid.

1.Calculate Moles of NaOH,

M = 0.850 M

V = 25 mL

Moles of NaOH = 0.02125

2. Calculate the moles of Acid

But, moles of diprotic acid = moles of NaOH

Since it is a diprotic acid it require 2 mole of NaOH (Diprotic gives 2H+)

So,

Moles of Acid required for neutralisation = 1/2 moles of NaOH

moles of Acid =

Moles of Acid = 0.010625

3.Calculate the molar mass of Acid

Mass = 5.692 g

Molar mass = 535.71 g

4.Check from the options which has Molar mass = 535 gram or around

a)C27H19012

= 27(mass of C) + 19(mass of H) + 12(mass of O)

= 27(12) + 19(1) + 12(16)

=  324 + 19 + 192

= 535 gram

Hence , A is correct option.

the temperature of the gas, in k, not celsius.