Astudent dissolves 12.g of sucrose c12h22o11 in 300.ml of a solvent with a density of 1.01/gml . the student notices that the volume of the solvent does not change when the sucrose dissolves in it. calculate the molarity and molality of the student's solution. round both of your answers to 2 significant digits.

Answer :  The molarity and molality of the student's solution is, 0.12 mol/L and 0.12 mol/kg respectively.

Explanation : Given,

Density of solvent = 1.01 g/mL

Molar mass of sucrose = 342.3 g/mole

Mass of sucrose = 12 g

Volume of solvent = 300 mL

First we have to calculate the mass of solvent.

Now we have to calculate the molarity of solution.

Now we have to calculate the molality.

Therefore, the molarity and molality of the student's solution is, 0.12 mol/L and 0.12 mol/kg respectively.

the correct answer would be d. hope this !

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.