When 3-methyl-2-pentene is treated with mercuric acetate, hg(o2cch3)2, in a thf-ethanol mixture and the resulting product reacted with nabh4 in basic solution, the principal product formed is which of these

a) 3-methyl-3-pentanol

b) 3-ethoxy-3-methylpentane

c) 3-methyl-2-pentanol

d) 2-ethoxy-3-methylpentane

e) 1-ethoxy-3-methylpentane

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

i don't see a text, but i am gonna assume this *orbit* the curved path, usually elliptical, described by a planet, satellite, spaceship, etc., around a celestial body, as the sun.

c

explanation: