What is the approximate ph of a 0.10 m solution of a weak acid that has a ka of 5 x10^-5 m?

pH = 2.66

Explanation:

weak acid:

∴ Ka = 5 E-5 M = [H+][A-]/[HA]

∴ [HA] = 0.10 M - [A-]

∴ [H+] = [A-]

⇒ Ka = [H+]²/(0.10 - [H+])

⇒ [H+]² + 5 E-5[H+] - 5 E-6 = 0

⇒ [H+] = 2.211 E-3 M

⇒ pH = - Log [H+]

⇒ pH = 2.6553

answer: e.   sour taste

explanation: acids are those substances which dissociates in water to give ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. acids are sour in taste. example: hcl

bases are those substances which dissociates in water to give ions or accepts ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. bases are bitter in taste. bases are slippery in nature.